△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD的...△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD
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![△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD的...△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD](/uploads/image/z/3718251-27-1.jpg?t=%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E7%82%B9D%2CE%E5%88%86%E5%88%AB%E5%9C%A8BC%2CAC%E8%BE%B9%E4%B8%8A%2C%E4%B8%94AE%3DCD%2CAD%E4%B8%8EBF%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9F.%E6%B1%82%E8%AF%81%E2%96%B3ABE%E5%85%A8%E7%AD%89%E4%BA%8E%E2%96%B3CAD%E5%92%8C%E6%B1%82%E8%A7%92BFD%E7%9A%84...%E2%96%B3ABC%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E7%82%B9D%2CE%E5%88%86%E5%88%AB%E5%9C%A8BC%2CAC%E8%BE%B9%E4%B8%8A%2C%E4%B8%94AE%3DCD%2CAD%E4%B8%8EBF%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9F.%E6%B1%82%E8%AF%81%E2%96%B3ABE%E5%85%A8%E7%AD%89%E4%BA%8E%E2%96%B3CAD%E5%92%8C%E6%B1%82%E8%A7%92BFD)
△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD的...△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD
△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD的...
△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD的度数.
△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD的...△ABC为等边三角形,点D,E分别在BC,AC边上,且AE=CD,AD与BF相交于点F.求证△ABE全等于△CAD和求角BFD
(1)AB=AC,
AE=CD,
∠BAE=∠ACD=60,
∴△ABE≌△CAD(SAS).
(2)△ABE≌△CAD,
∠EAF=∠ABE,
∠AFE=∠FBA+∠BAF
∠AFE=∠FAB+∠EAF=∠BAE=60,
∠BFD=∠AFE
∠BFD=60°.
三角形全等:
AE=CD AB=CA 角BAC=角ACD 有全等可得角BAE=角ABF=角BAF`````1
角BFD是三角形ABF的外角,角BFD=角ABF+角BAF``````2
有1,2 得 角BFD=角BAC
又三角形ABC等边
角BFD=角BAC=60度
先证全等 因为 AE等于CD。角C等于角BAC AB等于AC(ASA)
角DAC加角BAD等于60(角DAC等于角ABE)
角BFD等于60度
60°
1.∵AE=CD,AB=AC,∠EAB=∠DCA=60°
∴△ABE ≌ △CAD
2.60°