函数y=cos(2x-3π/4)-2√2(sinx)^2的最小正周期为_____.请写出过程,
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![函数y=cos(2x-3π/4)-2√2(sinx)^2的最小正周期为_____.请写出过程,](/uploads/image/z/3742105-49-5.jpg?t=%E5%87%BD%E6%95%B0y%3Dcos%282x-3%CF%80%2F4%29-2%E2%88%9A2%28sinx%29%5E2%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%BA_____.%E8%AF%B7%E5%86%99%E5%87%BA%E8%BF%87%E7%A8%8B%2C)
函数y=cos(2x-3π/4)-2√2(sinx)^2的最小正周期为_____.请写出过程,
函数y=cos(2x-3π/4)-2√2(sinx)^2的最小正周期为_____.请写出过程,
函数y=cos(2x-3π/4)-2√2(sinx)^2的最小正周期为_____.请写出过程,
y=cos(2x-3π/4)-2√2(sinx)^2
=cos(2x-3π/4)+√2[1-2(sinx)^2]-√2
=-√2/2*cos2x+√2/2*sin2x+√2cos2x- √2
=√2/2*cos2x+√2/2*sin2x-√2
=cos(2x-pi/4)-√2
T=2pi/2=pi
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