(2+1)(2²+1)(2²²+1)(2²²²+1).(2²n+1)=?
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![(2+1)(2²+1)(2²²+1)(2²²²+1).(2²n+1)=?](/uploads/image/z/3876039-63-9.jpg?t=%282%2B1%29%282%26%23178%3B%2B1%29%282%26%23178%3B%26%23178%3B%2B1%29%282%26%23178%3B%26%23178%3B%26%23178%3B%2B1%29.%282%26%23178%3Bn%2B1%29%3D%3F)
(2+1)(2²+1)(2²²+1)(2²²²+1).(2²n+1)=?
(2+1)(2²+1)(2²²+1)(2²²²+1).(2²n+1)=?
(2+1)(2²+1)(2²²+1)(2²²²+1).(2²n+1)=?
2^(2^(n+1))-1
初一应该是规律题,你应该抄错题了。
标准答案应该是原式左乘(2-1)反复使用平方差公式得到结果2^(2^(n+1))-1