已知1²+2²+3²+4²+……+n²=1/6n(n+1)(2n+1),求2²+4²+……+50²=
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 04:05:55
![已知1²+2²+3²+4²+……+n²=1/6n(n+1)(2n+1),求2²+4²+……+50²=](/uploads/image/z/3936086-62-6.jpg?t=%E5%B7%B2%E7%9F%A51%26%23178%3B%2B2%26%23178%3B%2B3%26%23178%3B%2B4%26%23178%3B%2B%E2%80%A6%E2%80%A6%2Bn%26%23178%3B%3D1%2F6n%28n%2B1%29%282n%2B1%29%2C%E6%B1%822%26%23178%3B%2B4%26%23178%3B%2B%E2%80%A6%E2%80%A6%2B50%26%23178%3B%3D)
已知1²+2²+3²+4²+……+n²=1/6n(n+1)(2n+1),求2²+4²+……+50²=
已知1²+2²+3²+4²+……+n²=1/6n(n+1)(2n+1),求2²+4²+……+50²=
已知1²+2²+3²+4²+……+n²=1/6n(n+1)(2n+1),求2²+4²+……+50²=
2²+4²+……+50²
= 4(1²+2²+……+25²)
= 4 (1/6 * 25 * 26 * 51)
= 2*25*26*17
= 22100