已知集合A={2,5,a²-3a+5},B={1,3,a²-6a+10},且A∩B={2,3},求实数a.
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![已知集合A={2,5,a²-3a+5},B={1,3,a²-6a+10},且A∩B={2,3},求实数a.](/uploads/image/z/3938943-39-3.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88A%3D%EF%BD%9B2%2C5%2Ca%26%23178%3B-3a%2B5%7D%2CB%3D%7B1%2C3%2Ca%26%23178%3B-6a%2B10%7D%2C%E4%B8%94A%E2%88%A9B%3D%EF%BD%9B2%2C3%EF%BD%9D%2C%E6%B1%82%E5%AE%9E%E6%95%B0a.)
已知集合A={2,5,a²-3a+5},B={1,3,a²-6a+10},且A∩B={2,3},求实数a.
已知集合A={2,5,a²-3a+5},B={1,3,a²-6a+10},且A∩B={2,3},求实数a.
已知集合A={2,5,a²-3a+5},B={1,3,a²-6a+10},且A∩B={2,3},求实数a.
A={2,5,a²-3a+5} ,B={1,3,a²-6a+10} A∩B={2,3}
所以3属于A a²-3a+5=3 a^2-3a+2=0 (a-2)(a-1)=0 a=1或2
而且2属于B a²-6a+10=2 a²-6a+8=0 (a-4)(a-2) a=2或4
所以 a=2
我才初中。。。。。。。。。
a²-3a+5 = 3 且 a²-6a+10 = 2
=》a²-3a+2 = 0 且 a²-6a+8 = 0
=》a=1或2 且 a=2或4
=> a = 2