(x+1)²-3(X+1)+12=0还有 y\4-y²=1
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 15:43:14
![(x+1)²-3(X+1)+12=0还有 y\4-y²=1](/uploads/image/z/3973626-18-6.jpg?t=%EF%BC%88x%2B1%EF%BC%89%26%23178%3B-3%28X%2B1%29%2B12%3D0%E8%BF%98%E6%9C%89+++y%5C4-y%26%23178%3B%3D1)
(x+1)²-3(X+1)+12=0还有 y\4-y²=1
(x+1)²-3(X+1)+12=0
还有 y\4-y²=1
(x+1)²-3(X+1)+12=0还有 y\4-y²=1
(x+1)²-3(X+1)+12
=[(x+1)-3/2]²+39/4>0
方程无实数解
(x+1)²-3(X+1)+12=0
x²+2x+1-3x-3+12=0
x²-x+8=0
△=(-1)²-4×8=-31<0
∴原方程无实数解
y/4-y²=1
y-4y²=4
-4y²+y-4=0
4y²-y+4=0
△=(-1)²-4×4×4=1-64=-63<0
∴原方程无实数解