cos(π/4+x)=4/5x∈(17π/12,7π/4),求(sin2x+2sin²x)/(1-tanx)
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cos(π/4+x)=4/5x∈(17π/12,7π/4),求(sin2x+2sin²x)/(1-tanx)
cos(π/4+x)=4/5x∈(17π/12,7π/4),求(sin2x+2sin²x)/(1-tanx)
cos(π/4+x)=4/5x∈(17π/12,7π/4),求(sin2x+2sin²x)/(1-tanx)
cos(2x-π)/[根号2cos(x+π/4)]=-1/5,0
cos(π/4+x)=3/5,17π/12
cos(π/4+X)=3/5,17π/12
cos(π/4+x)=3/5,17π/12
cos(π/4+x)=3/5,17π/12
cos(π/4+x)=3/5,17/12π
cos(π/4+x)=3/5,17π/12
cos(π/4+x)=3/5,17π/12
cos(π/4+x)=3/5,-17π/12
化简:cos(π/4-x)乘cos(π/4+x)
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化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π)
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