y=x²-2x+1/x²-1÷x²-x/x+1·5x试说明在左边代数式有意义的条件下,无论x为何值,y的值不变
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 10:51:03
![y=x²-2x+1/x²-1÷x²-x/x+1·5x试说明在左边代数式有意义的条件下,无论x为何值,y的值不变](/uploads/image/z/4328018-26-8.jpg?t=y%3Dx%26%23178%3B-2x%2B1%2Fx%26%23178%3B-1%C3%B7x%26%23178%3B-x%2Fx%2B1%C2%B75x%E8%AF%95%E8%AF%B4%E6%98%8E%E5%9C%A8%E5%B7%A6%E8%BE%B9%E4%BB%A3%E6%95%B0%E5%BC%8F%E6%9C%89%E6%84%8F%E4%B9%89%E7%9A%84%E6%9D%A1%E4%BB%B6%E4%B8%8B%2C%E6%97%A0%E8%AE%BAx%E4%B8%BA%E4%BD%95%E5%80%BC%2Cy%E7%9A%84%E5%80%BC%E4%B8%8D%E5%8F%98)
y=x²-2x+1/x²-1÷x²-x/x+1·5x试说明在左边代数式有意义的条件下,无论x为何值,y的值不变
y=x²-2x+1/x²-1÷x²-x/x+1·5x试说明在左边代数式有意义的条件下,无论x为何值,y的值不变
y=x²-2x+1/x²-1÷x²-x/x+1·5x试说明在左边代数式有意义的条件下,无论x为何值,y的值不变
当满足x≠±1时,y=((x-1)^2/(x+1)(x-1))*((x+1)/x(x-1))*5x=5.所以满足x≠±1时,无论x为何值,y的值不变