若log(a)x=2,log(b)x=3,log(c)x=6,则log(abc)x=?括号内为底数
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![若log(a)x=2,log(b)x=3,log(c)x=6,则log(abc)x=?括号内为底数](/uploads/image/z/4341459-3-9.jpg?t=%E8%8B%A5log%EF%BC%88a%EF%BC%89x%3D2%2Clog%EF%BC%88b%EF%BC%89x%3D3%2Clog%EF%BC%88c%EF%BC%89x%3D6%2C%E5%88%99log%EF%BC%88abc%EF%BC%89x%3D%3F%E6%8B%AC%E5%8F%B7%E5%86%85%E4%B8%BA%E5%BA%95%E6%95%B0)
若log(a)x=2,log(b)x=3,log(c)x=6,则log(abc)x=?括号内为底数
若log(a)x=2,log(b)x=3,log(c)x=6,则log(abc)x=?括号内为底数
若log(a)x=2,log(b)x=3,log(c)x=6,则log(abc)x=?括号内为底数
答案是 1
由题意知:x=a^2
x=b^3
x=c^6
故abc=x^(1/2+1/3+1/6)=x
故log(abc)x=log(x)x=1