16y²-16xy²+4x²y²/﹣2x²y+12xy-16y 约分求解下,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/21 14:24:15
![16y²-16xy²+4x²y²/﹣2x²y+12xy-16y 约分求解下,](/uploads/image/z/4480586-26-6.jpg?t=16y%26%23178%3B-16xy%26%23178%3B%EF%BC%8B4x%26%23178%3By%26%23178%3B%EF%BC%8F%EF%B9%A32x%26%23178%3By%EF%BC%8B12xy%EF%BC%8D16y+%E7%BA%A6%E5%88%86%E6%B1%82%E8%A7%A3%E4%B8%8B%2C)
16y²-16xy²+4x²y²/﹣2x²y+12xy-16y 约分求解下,
16y²-16xy²+4x²y²/﹣2x²y+12xy-16y 约分求解下,
16y²-16xy²+4x²y²/﹣2x²y+12xy-16y 约分求解下,
16y²-16xy²+4x²y²=(4y-2xy)²(使用的是完全平方的公式)=[2y(2-x)]²=4y²(2-x)
﹣2x²y+12xy-16y=-(2x²y-12xy+16y)=-2y(x²-6x+8)=-2y(x-2)(x-4)=2y(2-x)(x-4)
所以原式=4y²(2-x)/2y(2-x)(x-4)
=2y/(x-4)
原式=4y²(4-4x+x²) / [-2y(x²-6x+8)]
=4y²(x-2)(x-2) /[-2y(x-2)(x-4)]
=-2y(x-2) / (x-4)