1,观察下面算式,找规律并填空 :1/2*1=1-1/2 1/2*3=1\2-1/3 .根据以上规律解答下题:若有理数a,b满足|a-1|+(b-3)² =0 试求 1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+.+1(a+100)(b+100) 的值 2 (1-1/100)(1-1/99)(1-1/98).(1-1/3) 3
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![1,观察下面算式,找规律并填空 :1/2*1=1-1/2 1/2*3=1\2-1/3 .根据以上规律解答下题:若有理数a,b满足|a-1|+(b-3)² =0 试求 1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+.+1(a+100)(b+100) 的值 2 (1-1/100)(1-1/99)(1-1/98).(1-1/3) 3](/uploads/image/z/4992367-31-7.jpg?t=1%2C%E8%A7%82%E5%AF%9F%E4%B8%8B%E9%9D%A2%E7%AE%97%E5%BC%8F%2C%E6%89%BE%E8%A7%84%E5%BE%8B%E5%B9%B6%E5%A1%AB%E7%A9%BA+%3A1%2F2%2A1%3D1-1%2F2+1%2F2%2A3%3D1%5C2-1%2F3+.%E6%A0%B9%E6%8D%AE%E4%BB%A5%E4%B8%8A%E8%A7%84%E5%BE%8B%E8%A7%A3%E7%AD%94%E4%B8%8B%E9%A2%98%EF%BC%9A%E8%8B%A5%E6%9C%89%E7%90%86%E6%95%B0a%2Cb%E6%BB%A1%E8%B6%B3%7Ca-1%7C%2B%EF%BC%88b-3%EF%BC%89%26sup2%3B+%3D0+%E8%AF%95%E6%B1%82+1%2Fab%2B1%2F%28a%2B2%29%28b%2B2%29%2B1%2F%28a%2B4%29%28b%2B4%29%2B.%2B1%28a%2B100%29%28b%2B100%29+%E7%9A%84%E5%80%BC+2+%281-1%2F100%29%281-1%2F99%29%281-1%2F98%29.%281-1%2F3%29+3)
1,观察下面算式,找规律并填空 :1/2*1=1-1/2 1/2*3=1\2-1/3 .根据以上规律解答下题:若有理数a,b满足|a-1|+(b-3)² =0 试求 1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+.+1(a+100)(b+100) 的值 2 (1-1/100)(1-1/99)(1-1/98).(1-1/3) 3
1,观察下面算式,找规律并填空 :1/2*1=1-1/2 1/2*3=1\2-1/3 .根据以上规律解答下题:若有理数a,b满足|a-1|+(b-3)² =0 试求 1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+.+1(a+100)(b+100) 的值 2 (1-1/100)(1-1/99)(1-1/98).(1-1/3) 3 已知a=2008*2007-2008/2007*2006+2006 b=2007*2007-2007/2006*2006+2006 c=2006*2005-2005/2005*2004-2005 求a*b*c的值 附:第一题1/3就是三分之一的意思
1,观察下面算式,找规律并填空 :1/2*1=1-1/2 1/2*3=1\2-1/3 .根据以上规律解答下题:若有理数a,b满足|a-1|+(b-3)² =0 试求 1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+.+1(a+100)(b+100) 的值 2 (1-1/100)(1-1/99)(1-1/98).(1-1/3) 3
(1) 102/103
(2) 1/50
(3) 题目抄得不好,也可能抄错了,
是不是c=(2006*2005-2005)/(2005*2004-2005)?
如果是,那么答案是2005/2003
如果c=(2006*2005-2005)/(2005*2004+2005)那么答案是1
1. a=1,b=3. 1/(1*3)+1/(1*5)...=1/2*(1-1/3+1/3-...+1/101-103)=51/103
2. =99/100*98/99*...2/3=1/50
3. 你写的也太乱了吧 看不懂 既不知道运算先后 也不确定你写的对不对 没规律? 帮不了你
不会
(1)由有理数a,b满足|a-1|+(b-3)² =0 得,a=1,b=3
1/2*1=1-1/2 则2/1*3=1-1/3
1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+......+1(a+100)(b+100)
=1/1*3+1/(1+2)*(3+2)+1/(1+4)*(3+4)+......+1/(1+100)*(3+100)<...
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(1)由有理数a,b满足|a-1|+(b-3)² =0 得,a=1,b=3
1/2*1=1-1/2 则2/1*3=1-1/3
1/ab+1/(a+2)(b+2)+1/(a+4)(b+4)+......+1(a+100)(b+100)
=1/1*3+1/(1+2)*(3+2)+1/(1+4)*(3+4)+......+1/(1+100)*(3+100)
=2*[1-1/3+1/3-1/5+1/5-1/7+1/7......+1/101-1/103]
=204/103
(2) 2 (1-1/100)(1-1/99)(1-1/98)......(1-1/3)
=2(99/100)(98/99)(97/98)......(2/3)
=1/25
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