-(2x+1)²=3(2x+1)²-4
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![-(2x+1)²=3(2x+1)²-4](/uploads/image/z/5253688-64-8.jpg?t=-%282x%2B1%29%26%23178%3B%3D3%282x%2B1%29%26%23178%3B-4)
-(2x+1)²=3(2x+1)²-4
-(2x+1)²=3(2x+1)²-4
-(2x+1)²=3(2x+1)²-4
-(2x+1)²=3(2x+1)²-4
3(2x+1)²+(2x+1)²-4=0
4(2x+1)² -4=0
(2X+1)²=1
2X+1=正负1
所以X1=0,X2=-1
解
-(2x+1)²=3(2x+1)²-4
∴4=3(2x+1)²+(2x+1)²
即4(2x+1)²=4
∴(2x+1)²=1
∴2x+1=±1
∴2x+1=1或2x+1=-1
∴x=0,或x=-1