MATLAB矩阵除法y=Ax左除与右除的解我构造了y=Ax样的矩阵乘法,如下%%%%%%%%%%%%%%A=randi(20,4,5);x=randi(10,5,1);y=A*x;A*(A\y)yA\yx%%%%%%%%%%%%%%运行后发现A*(A\y)与y值相同(差无穷小),但是A\y与x并不相同,这是
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![MATLAB矩阵除法y=Ax左除与右除的解我构造了y=Ax样的矩阵乘法,如下%%%%%%%%%%%%%%A=randi(20,4,5);x=randi(10,5,1);y=A*x;A*(A\y)yA\yx%%%%%%%%%%%%%%运行后发现A*(A\y)与y值相同(差无穷小),但是A\y与x并不相同,这是](/uploads/image/z/5427181-37-1.jpg?t=MATLAB%E7%9F%A9%E9%98%B5%E9%99%A4%E6%B3%95y%3DAx%E5%B7%A6%E9%99%A4%E4%B8%8E%E5%8F%B3%E9%99%A4%E7%9A%84%E8%A7%A3%E6%88%91%E6%9E%84%E9%80%A0%E4%BA%86y%3DAx%E6%A0%B7%E7%9A%84%E7%9F%A9%E9%98%B5%E4%B9%98%E6%B3%95%2C%E5%A6%82%E4%B8%8B%25%25%25%25%25%25%25%25%25%25%25%25%25%25A%3Drandi%2820%2C4%2C5%29%3Bx%3Drandi%2810%2C5%2C1%29%3By%3DA%2Ax%3BA%2A%28A%5Cy%29yA%5Cyx%25%25%25%25%25%25%25%25%25%25%25%25%25%25%E8%BF%90%E8%A1%8C%E5%90%8E%E5%8F%91%E7%8E%B0A%2A%28A%5Cy%29%E4%B8%8Ey%E5%80%BC%E7%9B%B8%E5%90%8C%EF%BC%88%E5%B7%AE%E6%97%A0%E7%A9%B7%E5%B0%8F%EF%BC%89%2C%E4%BD%86%E6%98%AFA%5Cy%E4%B8%8Ex%E5%B9%B6%E4%B8%8D%E7%9B%B8%E5%90%8C%2C%E8%BF%99%E6%98%AF)
MATLAB矩阵除法y=Ax左除与右除的解我构造了y=Ax样的矩阵乘法,如下%%%%%%%%%%%%%%A=randi(20,4,5);x=randi(10,5,1);y=A*x;A*(A\y)yA\yx%%%%%%%%%%%%%%运行后发现A*(A\y)与y值相同(差无穷小),但是A\y与x并不相同,这是
MATLAB矩阵除法y=Ax左除与右除的解
我构造了y=Ax样的矩阵乘法,如下
%%%%%%%%%%%%%%
A=randi(20,4,5);
x=randi(10,5,1);
y=A*x;
A*(A\y)
y
A\y
x
%%%%%%%%%%%%%%
运行后发现A*(A\y)与y值相同(差无穷小),但是A\y与x并不相同,这是为什么?
粘贴党,不懂装懂者不要冒泡,网页上的我都看到,也不要粘MATLAB说明文档,我看过不能解释这个问题.
MATLAB矩阵除法y=Ax左除与右除的解我构造了y=Ax样的矩阵乘法,如下%%%%%%%%%%%%%%A=randi(20,4,5);x=randi(10,5,1);y=A*x;A*(A\y)yA\yx%%%%%%%%%%%%%%运行后发现A*(A\y)与y值相同(差无穷小),但是A\y与x并不相同,这是
原因很简单:
未知数x是5个元素,但只有4个方程,方程组Ax=y不封闭,共有无穷多个解.用randi生成的x只是无穷多个解中的一个,而A\y求出来的是另一个解.