先化简,再求值,x²-1/(x+1)(x-2)除以x/2x-4,其中x=½
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![先化简,再求值,x²-1/(x+1)(x-2)除以x/2x-4,其中x=½](/uploads/image/z/5456418-42-8.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BC%2Cx%26%23178%3B-1%2F%EF%BC%88x%2B1%EF%BC%89%EF%BC%88x-2%EF%BC%89%E9%99%A4%E4%BB%A5x%2F2x-4%2C%E5%85%B6%E4%B8%ADx%EF%BC%9D%26%23189%3B)
先化简,再求值,x²-1/(x+1)(x-2)除以x/2x-4,其中x=½
先化简,再求值,x²-1/(x+1)(x-2)除以x/2x-4,其中x=½
先化简,再求值,x²-1/(x+1)(x-2)除以x/2x-4,其中x=½
x(2次方)-1/x(2次方)-x-2除以x/2x-4
=(x-1)(x+1)/(x-2)(x+1)÷x/2(x-2)
=(x-1)/(x-2)*2(x-2)/x
=2(x-1)/x
=2-2/x
=2-2/(1/2)
=2-4
=-2