4/3x-2y+3/2x-5y=10 5/3x-2y-2/2x-5y=1 用换元法这个方程组用换元法解4/(3x-2y)+3/(2x-5y)=10① 5/(3x-2y)- 2/(2x-5y)= 1 ②
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/23 18:57:29
![4/3x-2y+3/2x-5y=10 5/3x-2y-2/2x-5y=1 用换元法这个方程组用换元法解4/(3x-2y)+3/(2x-5y)=10① 5/(3x-2y)- 2/(2x-5y)= 1 ②](/uploads/image/z/559332-36-2.jpg?t=4%2F3x-2y%2B3%2F2x-5y%3D10+5%2F3x-2y-2%2F2x-5y%3D1+%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%E8%BF%99%E4%B8%AA%E6%96%B9%E7%A8%8B%E7%BB%84%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%E8%A7%A34%2F%EF%BC%883x-2y%EF%BC%89%2B3%2F%EF%BC%882x-5y%EF%BC%89%3D10%E2%91%A0+5%2F%EF%BC%883x-2y%EF%BC%89-+2%2F%EF%BC%882x-5y%EF%BC%89%3D+1+%E2%91%A1)
4/3x-2y+3/2x-5y=10 5/3x-2y-2/2x-5y=1 用换元法这个方程组用换元法解4/(3x-2y)+3/(2x-5y)=10① 5/(3x-2y)- 2/(2x-5y)= 1 ②
4/3x-2y+3/2x-5y=10 5/3x-2y-2/2x-5y=1 用换元法
这个方程组用换元法解
4/(3x-2y)+3/(2x-5y)=10①
5/(3x-2y)- 2/(2x-5y)= 1 ②
4/3x-2y+3/2x-5y=10 5/3x-2y-2/2x-5y=1 用换元法这个方程组用换元法解4/(3x-2y)+3/(2x-5y)=10① 5/(3x-2y)- 2/(2x-5y)= 1 ②
②*10得50/(3x-2y)- 20/(2x-5y)= 10
①-上式得2\(3x-2y)=1\(2x-5y)
所以x=8y 带入①得y=1\22
所以x=4\11
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
5x^3y(x-y)^3-10x^4y^3(y-x)^2因式分解
5x^3y(x-y)^3-10x^4y^3(y-x)^2
5X^3Y(X-Y)-10X^4Y^3(Y-X)^2因式分解
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
3(2X+Y)+(2(2x-Y)=6 (8X+4y)-(10X-5Y)=2
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
4x-2*(10-x)-10=5y-3*(10-y)x+y=14
3X=5Y (X+Y)*3X=(2Y+X)*4+2*2
5/4(x+y)(-x-y)^3*[-4/3(x-y)]*[-3/5(y-x)^2]
化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2