若(x²+px+q)(x²-3x+2)的乘积中不含x³和x²项,求p,q的值.
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/20 13:58:27
![若(x²+px+q)(x²-3x+2)的乘积中不含x³和x²项,求p,q的值.](/uploads/image/z/5623248-48-8.jpg?t=%E8%8B%A5%28x%26%23178%3B%2Bpx%2Bq%29%28x%26%23178%3B-3x%2B2%29%E7%9A%84%E4%B9%98%E7%A7%AF%E4%B8%AD%E4%B8%8D%E5%90%ABx%26%23179%3B%E5%92%8Cx%26%23178%3B%E9%A1%B9%2C%E6%B1%82p%2Cq%E7%9A%84%E5%80%BC.)
若(x²+px+q)(x²-3x+2)的乘积中不含x³和x²项,求p,q的值.
若(x²+px+q)(x²-3x+2)的乘积中不含x³和x²项,求p,q的值.
若(x²+px+q)(x²-3x+2)的乘积中不含x³和x²项,求p,q的值.
因为乘积中不含x²项,且x²项的系数为(-3p+q+2)=0
因为乘积中不含x³项,且x³项的系数为(-3+p)=0
所以,解得p=3,q=7
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