若根号2x+1+[y-2]²+ |z-1|=0,求代数式(xy)²的值
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![若根号2x+1+[y-2]²+ |z-1|=0,求代数式(xy)²的值](/uploads/image/z/570520-64-0.jpg?t=%E8%8B%A5%E6%A0%B9%E5%8F%B72x%EF%BC%8B1%EF%BC%8B%5By-2%5D%26%23178%3B%EF%BC%8B+%7Cz-1%7C%EF%BC%9D0%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%88xy%EF%BC%89%26%23178%3B%E7%9A%84%E5%80%BC)
若根号2x+1+[y-2]²+ |z-1|=0,求代数式(xy)²的值
若根号2x+1+[y-2]²+ |z-1|=0,求代数式(xy)²的值
若根号2x+1+[y-2]²+ |z-1|=0,求代数式(xy)²的值
根号2x+1+[y-2]²+ |z-1|=0,
根号2x+1>=0,[y-2]²>=0,|z-1|>=0,
2x+1=0
y-2=0
z-1=0
x=-1/2,y=2,z=1
(xy)²=1
因为√、平方、绝对值都是非负的,和为0则每个都是0
所以
2x+1=0
x=-1/2
y-2=0
y=2
z-1=0
z=1
(xy)²=(-1)²=1
z没用到?
还是求xy的z次方?结果是-1?
都是非负数相+,都为0