作业帮[x(x²y-xy)-y(x²-x³y)]÷3x²y[x(x²y²-xy)-y(x²-x³y)]÷3x²y
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/11 21:48:59
![[x(x²y-xy)-y(x²-x³y)]÷3x²y[x(x²y²-xy)-y(x²-x³y)]÷3x²y](/uploads/image/z/585368-8-8.jpg?t=%5Bx%28x%26%23178%3By-xy%29-y%28x%26%23178%3B-x%26%23179%3By%29%5D%C3%B73x%26%23178%3By%5Bx%28x%26%23178%3By%26%23178%3B-xy%29-y%28x%26%23178%3B-x%26%23179%3By%29%5D%C3%B73x%26%23178%3By)
[x(x²y-xy)-y(x²-x³y)]÷3x²y[x(x²y²-xy)-y(x²-x³y)]÷3x²y
[x(x²y-xy)-y(x²-x³y)]÷3x²y
[x(x²y²-xy)-y(x²-x³y)]÷3x²y
[x(x²y-xy)-y(x²-x³y)]÷3x²y[x(x²y²-xy)-y(x²-x³y)]÷3x²y
[x(x²y-xy)-y(x²-x³y)]÷3x²y
=x^2y[(x-1)-(1-xy)]÷3x²y
=[(x-1)-(1-xy)]÷3
=(x-2+xy)/3
原式=（x^3y^2-x^2y-x^2y+x^3y^2)÷3x^2y
=(2x^3y^2-2x^2y)÷3x^2y
=2/3*xy-1/3