ab(a²-b²+bc(b²-c²)+ac(c²-a²)因式分解
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ab(a²-b²+bc(b²-c²)+ac(c²-a²)因式分解
ab(a²-b²+bc(b²-c²)+ac(c²-a²)因式分解
ab(a²-b²+bc(b²-c²)+ac(c²-a²)因式分解
原式=a^3b-ab^3+bc(b^2-c^2)+ac^3-a^3c
=a^3(b-c)-a(b^3-c^3)+bc(b^2-c^2)
=a^3(b-c)-a(b-c)(b^2+bc+c^2)+bc(b+c)(b-c)
=[a^3-a(b^2+bc+c^2)+bc(b+c)](b-c)
同理原式含有(a-b),(c-a)因式
原式=-(a-b)(b-c)(c-a)(a+b+c)