(1)3x+3/√x+1 (2)√a²-ab/√a²+ab(2)a≥b≥0
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![(1)3x+3/√x+1 (2)√a²-ab/√a²+ab(2)a≥b≥0](/uploads/image/z/7181630-62-0.jpg?t=%EF%BC%881%EF%BC%893x%2B3%2F%E2%88%9Ax%2B1+%282%29%E2%88%9Aa%26%23178%3B-ab%2F%E2%88%9Aa%26%23178%3B%2Bab%282%29a%E2%89%A5b%E2%89%A50)
(1)3x+3/√x+1 (2)√a²-ab/√a²+ab(2)a≥b≥0
(1)3x+3/√x+1 (2)√a²-ab/√a²+ab
(2)a≥b≥0
(1)3x+3/√x+1 (2)√a²-ab/√a²+ab(2)a≥b≥0
(1)3x+3/√x+1
=3(X+1)/√x+1
=3√x+1
(2)√a²-ab/√a²+ab
=(√a²-ab)²/[√(a²+ab)√(a²-ab)]
=(a²-ab)/√(a^4-a²b²)