1.已知x+2y+3z=104x+3y+2z=15求x+y+z=?2.将二元一次方程2x+3y-4=0化为y=kx+m的形式,并求m分之k的值.问此两题,
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![1.已知x+2y+3z=104x+3y+2z=15求x+y+z=?2.将二元一次方程2x+3y-4=0化为y=kx+m的形式,并求m分之k的值.问此两题,](/uploads/image/z/8483652-36-2.jpg?t=1.%E5%B7%B2%E7%9F%A5x%2B2y%2B3z%3D104x%2B3y%2B2z%3D15%E6%B1%82x%2By%2Bz%3D%3F2.%E5%B0%86%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B2x%2B3y-4%3D0%E5%8C%96%E4%B8%BAy%3Dkx%2Bm%E7%9A%84%E5%BD%A2%E5%BC%8F%2C%E5%B9%B6%E6%B1%82m%E5%88%86%E4%B9%8Bk%E7%9A%84%E5%80%BC.%E9%97%AE%E6%AD%A4%E4%B8%A4%E9%A2%98%2C)
1.已知x+2y+3z=104x+3y+2z=15求x+y+z=?2.将二元一次方程2x+3y-4=0化为y=kx+m的形式,并求m分之k的值.问此两题,
1.已知x+2y+3z=10
4x+3y+2z=15
求x+y+z=?
2.将二元一次方程2x+3y-4=0化为y=kx+m的形式,并求m分之k的值.
问此两题,
1.已知x+2y+3z=104x+3y+2z=15求x+y+z=?2.将二元一次方程2x+3y-4=0化为y=kx+m的形式,并求m分之k的值.问此两题,
将两个式子相加,得到
5x+5y+5z=25
从而
x+y+z=5
第二题:
y=-2x/3+4/3
m=4/3
k=-2/3
所以m分之k等于
-1/2
1式+2式:5x+5y+5z=25
x+y+z=5
3y=-2x+4
y=-2/3x+4/3
k=-2/3,m=4/3
k/m=-2/4=-1/2
1.
x+2y+3z=10 -------(1)
4x+3y+2z=15 ------(2)
(1)+(2)=5(X+Y+Z)=25所以X+Y+Z=5
2.
Y=-2/3X+4/3
所以K/M=-1/2
2. y=-2/3x-4/3
1.把已知的两式相加得:5x+5y+5z=25
所以x+y+z=5
2.3y=4-2x
y=(4-2x)/3=-2/3x+4/3
所以k=-2/3,m=4/3,
m分之k=-1/2