已知集合A={(x,y)∣(y-3)/(x-2)=a+1},B={(x,y)∣(a^2-1)x+(a-1)y=30},若A∩B=空集,求实数a的值
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![已知集合A={(x,y)∣(y-3)/(x-2)=a+1},B={(x,y)∣(a^2-1)x+(a-1)y=30},若A∩B=空集,求实数a的值](/uploads/image/z/8560521-9-1.jpg?t=%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88A%3D%7B%28x%2Cy%29%E2%88%A3%28y-3%29%2F%28x-2%29%3Da%2B1%7D%2CB%3D%7B%28x%2Cy%29%E2%88%A3%28a%5E2-1%29x%2B%28a-1%29y%3D30%7D%2C%E8%8B%A5A%E2%88%A9B%3D%E7%A9%BA%E9%9B%86%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%80%BC)
已知集合A={(x,y)∣(y-3)/(x-2)=a+1},B={(x,y)∣(a^2-1)x+(a-1)y=30},若A∩B=空集,求实数a的值
已知集合A={(x,y)∣(y-3)/(x-2)=a+1},B={(x,y)∣(a^2-1)x+(a-1)y=30},若A∩B=空集,求实数a的值
已知集合A={(x,y)∣(y-3)/(x-2)=a+1},B={(x,y)∣(a^2-1)x+(a-1)y=30},若A∩B=空集,求实数a的值
计算两直线方程的交点,x=1+15/(a^2-1)-3/(2a-2),要为空集,必须x无解,则a=-1或+1,经验证均满足。
要么平行,斜率相等,a=-1,要么直线交与点(2,3),带入第二个方程即可得a=-5.a=-7/2