三角形内角满足cos^2(C)-cos^2(A)+sin^2(A+C)-sinA*sinB=0,求角C的值
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![三角形内角满足cos^2(C)-cos^2(A)+sin^2(A+C)-sinA*sinB=0,求角C的值](/uploads/image/z/8692607-47-7.jpg?t=%E4%B8%89%E8%A7%92%E5%BD%A2%E5%86%85%E8%A7%92%E6%BB%A1%E8%B6%B3cos%5E2%EF%BC%88C%EF%BC%89-cos%5E2%EF%BC%88A%EF%BC%89%2Bsin%5E2%EF%BC%88A%2BC%EF%BC%89-sinA%2AsinB%3D0%2C%E6%B1%82%E8%A7%92C%E7%9A%84%E5%80%BC)
三角形内角满足cos^2(C)-cos^2(A)+sin^2(A+C)-sinA*sinB=0,求角C的值
三角形内角满足cos^2(C)-cos^2(A)+sin^2(A+C)-sinA*sinB=0,求角C的值
三角形内角满足cos^2(C)-cos^2(A)+sin^2(A+C)-sinA*sinB=0,求角C的值
根据正弦定理 就可以做