设x,y满足2x-y+2>=0,8x-y-4=0,y>=0,若目标函数z=abx+y(a>0,b>0)的最大值是8,则a+b的最小值我已经算出ab=4了 接下去该怎么办QAQ
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![设x,y满足2x-y+2>=0,8x-y-4=0,y>=0,若目标函数z=abx+y(a>0,b>0)的最大值是8,则a+b的最小值我已经算出ab=4了 接下去该怎么办QAQ](/uploads/image/z/8863602-42-2.jpg?t=%E8%AE%BEx%2Cy%E6%BB%A1%E8%B6%B32x-y%2B2%3E%3D0%2C8x-y-4%3D0%2Cy%3E%3D0%2C%E8%8B%A5%E7%9B%AE%E6%A0%87%E5%87%BD%E6%95%B0z%3Dabx%2By%28a%3E0%2Cb%3E0%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E6%98%AF8%2C%E5%88%99a%2Bb%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%88%91%E5%B7%B2%E7%BB%8F%E7%AE%97%E5%87%BAab%3D4%E4%BA%86+%E6%8E%A5%E4%B8%8B%E5%8E%BB%E8%AF%A5%E6%80%8E%E4%B9%88%E5%8A%9EQAQ)
设x,y满足2x-y+2>=0,8x-y-4=0,y>=0,若目标函数z=abx+y(a>0,b>0)的最大值是8,则a+b的最小值我已经算出ab=4了 接下去该怎么办QAQ
设x,y满足2x-y+2>=0,8x-y-4=0,y>=0,若目标函数z=abx+y(a>0,b>0)的最大值是8,则a+b的最小值
我已经算出ab=4了 接下去该怎么办QAQ
设x,y满足2x-y+2>=0,8x-y-4=0,y>=0,若目标函数z=abx+y(a>0,b>0)的最大值是8,则a+b的最小值我已经算出ab=4了 接下去该怎么办QAQ
ab=4,两正数的积一定,当他们相等时和最小,a=b=2,
a+b的最小值=2+2=4.
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