高数一试题解答1.设函数f(x-1)=x2-x,则f(x)=( )A.x(x-1) B.x(x+1)C.(x-1)2-(x-1) D.(x+1)(x-2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 16:13:56
![高数一试题解答1.设函数f(x-1)=x2-x,则f(x)=( )A.x(x-1) B.x(x+1)C.(x-1)2-(x-1) D.(x+1)(x-2)](/uploads/image/z/8909391-39-1.jpg?t=%E9%AB%98%E6%95%B0%E4%B8%80%E8%AF%95%E9%A2%98%E8%A7%A3%E7%AD%941%EF%BC%8E%E8%AE%BE%E5%87%BD%E6%95%B0f%28x-1%29%3Dx2-x%2C%E5%88%99f%28x%29%3D%EF%BC%88+%EF%BC%89A%EF%BC%8Ex%28x-1%29+B%EF%BC%8Ex%28x%2B1%29C%EF%BC%8E%28x-1%292-%28x-1%29+D%EF%BC%8E%28x%2B1%29%28x-2%29)
高数一试题解答1.设函数f(x-1)=x2-x,则f(x)=( )A.x(x-1) B.x(x+1)C.(x-1)2-(x-1) D.(x+1)(x-2)
高数一试题解答
1.设函数f(x-1)=x2-x,则f(x)=( )
A.x(x-1) B.x(x+1)
C.(x-1)2-(x-1) D.(x+1)(x-2)
高数一试题解答1.设函数f(x-1)=x2-x,则f(x)=( )A.x(x-1) B.x(x+1)C.(x-1)2-(x-1) D.(x+1)(x-2)
设x-1=t
所以x=1+t
f(t)=(1+t)平方-(1+t)=t(1+t)
还原变为f(X)=x(x+1)
选B,X^2-X=X(X-1)吧X-1替换成X那么原来的X就等于X+1了,所以就是选B了
B;
设x-1=t
=>x=t+1
=>f(t)=(t+1)(t+1)-(t+1)
=>f(t)=t*(t+1)
把X代替T就可以得B答案