已知6a²+12b²=17ab【a≠0,b≠0】,求a-b/a+b-a+b/a-b的值已知6a²+12b²=17ab【a≠0,b≠0】,求[a-b/a+b]-[a+b/a-b]的值
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![已知6a²+12b²=17ab【a≠0,b≠0】,求a-b/a+b-a+b/a-b的值已知6a²+12b²=17ab【a≠0,b≠0】,求[a-b/a+b]-[a+b/a-b]的值](/uploads/image/z/9296459-35-9.jpg?t=%E5%B7%B2%E7%9F%A56a%26%23178%3B%2B12b%26%23178%3B%3D17ab%E3%80%90a%E2%89%A00%2Cb%E2%89%A00%E3%80%91%2C%E6%B1%82a-b%2Fa%2Bb-a%2Bb%2Fa-b%E7%9A%84%E5%80%BC%E5%B7%B2%E7%9F%A56a%26%23178%3B%2B12b%26%23178%3B%3D17ab%E3%80%90a%E2%89%A00%2Cb%E2%89%A00%E3%80%91%2C%E6%B1%82%5Ba-b%2Fa%2Bb%5D-%5Ba%2Bb%2Fa-b%5D%E7%9A%84%E5%80%BC)
已知6a²+12b²=17ab【a≠0,b≠0】,求a-b/a+b-a+b/a-b的值已知6a²+12b²=17ab【a≠0,b≠0】,求[a-b/a+b]-[a+b/a-b]的值
已知6a²+12b²=17ab【a≠0,b≠0】,求a-b/a+b-a+b/a-b的值
已知6a²+12b²=17ab【a≠0,b≠0】,求[a-b/a+b]-[a+b/a-b]的值
已知6a²+12b²=17ab【a≠0,b≠0】,求a-b/a+b-a+b/a-b的值已知6a²+12b²=17ab【a≠0,b≠0】,求[a-b/a+b]-[a+b/a-b]的值
已知6a²+12b²=17ab【a≠0,b≠0】,
6a²/b²-17a/b+12=0;
(2a/b-3)(3a/b-4)=0;
a/b=3/2;或a/b=4/3;
求a-b/a+b-a+b/a-b
=((a-b)²-(a+b)²)/(a²-b²)
=(a²+b²-2ab-a²-b²-2ab)/(a²-b²)
=(-4ab)/(a²-b²)
=(-4a/b)/(a²/b²-1)
a/b=3/2时,原式=(-4×(3/2))/(9/4-1)=-24/5;
a/b=4/3时,原式=(-4×4/3)/(16/9-1)=-48/7;
很高兴为您解答,skyhunter002为您答疑解惑
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这。。。
a-b/a+b-a+b/a-b
怎么看都是0啊,你确定没括号神马的?
6a²-17ab+12b²=0,两同除以b²得:
6t²-17t+12=0 (t=a/b)
(2t-3)(3t-4)=0
t1=3/2,t2=4/3
当t=3/2时,
先算:(a-b)/(a+b)=[3/2-1]/[3/2+1=]=1/5
所以原式=1/5-5=-24/5
当t=4/3时,
先还是算(a-b)/(a+b)=[4/3-1]/[4/3+1]=1/7
原式=1/7-7=-48/7