根据以下函数关系,对输入的不同的x值,计算出相应的y值.0 x<0y= x 0≤x<1010 10≤x<20-0.5x+20 20≤x<40# include "stdio.h"void main( ){ int x,c;float y;scanf("%d",&x);if (________) c=-1;else c=__________;switch (c){ case -1
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![根据以下函数关系,对输入的不同的x值,计算出相应的y值.0 x<0y= x 0≤x<1010 10≤x<20-0.5x+20 20≤x<40# include](/uploads/image/z/11693093-5-3.jpg?t=%E6%A0%B9%E6%8D%AE%E4%BB%A5%E4%B8%8B%E5%87%BD%E6%95%B0%E5%85%B3%E7%B3%BB%2C%E5%AF%B9%E8%BE%93%E5%85%A5%E7%9A%84%E4%B8%8D%E5%90%8C%E7%9A%84x%E5%80%BC%2C%E8%AE%A1%E7%AE%97%E5%87%BA%E7%9B%B8%E5%BA%94%E7%9A%84y%E5%80%BC.0+x%EF%BC%9C0y%3D+x+0%E2%89%A4x%EF%BC%9C1010+10%E2%89%A4x%EF%BC%9C20-0.5x%2B20+20%E2%89%A4x%EF%BC%9C40%23+include+%22stdio.h%22void+main%28+%29%7B+int+x%2Cc%3Bfloat+y%3Bscanf%28%22%25d%22%2C%26x%29%3Bif+%28________%29+c%3D-1%3Belse+c%3D__________%3Bswitch+%28c%29%7B+case+-1)
根据以下函数关系,对输入的不同的x值,计算出相应的y值.0 x<0y= x 0≤x<1010 10≤x<20-0.5x+20 20≤x<40# include "stdio.h"void main( ){ int x,c;float y;scanf("%d",&x);if (________) c=-1;else c=__________;switch (c){ case -1
根据以下函数关系,对输入的不同的x值,计算出相应的y值.
0 x<0
y= x 0≤x<10
10 10≤x<20
-0.5x+20 20≤x<40
# include "stdio.h"
void main( )
{ int x,c;
float y;
scanf("%d",&x);
if (________) c=-1;
else c=__________;
switch (c)
{ case -1:y=0; break;
case 0:y=x; break;
case 1:y=10; break;
case 2:
case 3:y=-0.5*x+20; break;
default:y=-2;
}
if (_______) printf("y=%f\n",y);
else printf("error\n");
}
根据以下函数关系,对输入的不同的x值,计算出相应的y值.0 x<0y= x 0≤x<1010 10≤x<20-0.5x+20 20≤x<40# include "stdio.h"void main( ){ int x,c;float y;scanf("%d",&x);if (________) c=-1;else c=__________;switch (c){ case -1
# include "stdio.h"
void main( )
{ int x,c;
float y;
scanf("%d",&x);
if (x