对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,
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![对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,](/uploads/image/z/12575982-30-2.jpg?t=%E5%AF%B9%E6%95%B0%EF%BC%9Alog2%5E3%3Dp+log3%5E7%3Dq+log12%5E42%3D%3F%E5%88%9A%E5%88%9A%E5%AD%A6%E5%AF%B9%E6%95%B0%E8%BF%98%E4%B8%8D%E5%A4%AA%E7%86%9F%2C%E5%AF%B9%E6%95%B0%EF%BC%9Alog2%5E3%3Dp+log3%5E7%3Dq+log12%5E42%3D%3F%E5%88%9A%E5%88%9A%E5%AD%A6%E5%AF%B9%E6%95%B0%E8%BF%98%E4%B8%8D%E5%A4%AA%E7%86%9F%2C)
对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,
对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,
对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,
对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,
解log12(42)
=lg42/lg12
=(lg2+lg3+lg7)/(lg2^2+lg3)
=(lg2+lg3+lg7)/(2lg2+lg3)
=(lg2/lg3+lg3/lg3+lg7/lg3)/(2lg2/lg3+1)
=(log3(2)+1+log3(7))/(2log3(2)+1)
=(1/log2(3)+1+log3(7))/(2/log2(3)+1)
=(1/p+1+q)/(2/p+1)
=(1+p+pq)/(2+p)
对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,对数:log2^3=p log3^7=q log12^42=?刚刚学对数还不太熟,
设p=log2*3,q=log3*2,r=log2*(log3*2),则大小关系为
log3 7×log2 3=log2 7.这是为什么?对数解题有哪些要点?
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设p=log2(3)、Q=log2【log3(2)】、R=log2【log3(2)】,则它们的大小关系
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(log2 6)×(log3 6)-(log2 3+log3 2)=
(log2 6)×(log3 6)-(log2 3+log3 2)=
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log3为底 2的对数=log2为底 3的x次方的对数则x等于?
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计算log2(为底的)3(的对数)×log3(为底的)4(的对数)=
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