2∧x=3 log[4∧(8/3)]=y 则x+2y=

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2∧x=3 log[4∧(8/3)]=y 则x+2y=

2∧x=3 log[4∧(8/3)]=y 则x+2y=
2∧x=3 log[4∧(8/3)]=y 则x+2y=

2∧x=3 log[4∧(8/3)]=y 则x+2y=
x=log2(3)
y=lg(8/3)/lg4
=lg(8/3)/2lg2
=1/2*log2(8/3)
所以x+2y=log2(3)+log2(8/3)
=log2(3×8/3)
=log2(8)
=log2(2³)
=3