设(X,Y)的概率密度为f(x,y)=x+y (0
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设(X,Y)的概率密度为f(x,y)=x+y (0
设(X,Y)的概率密度为f(x,y)=x+y (0
设(X,Y)的概率密度为f(x,y)=x+y (0
f(x,y)=x+y (0
楼主的答案计算有误,min(x,y)中,当0
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