将三颗骰子各投一次,记事件A为“三个点数都不相同”,B为“至少出现一个6点,则概率P(A/B)P(A/B)=P(AB)/P(B)P(AB)=60/216,P(B)=1- P(B逆)=1- 5*5*5/(6*6*6)=1- 125/216= 91/216故:P(A/B)=(60/216)/(91/216)=60/91P(AB)=60/216?这
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![将三颗骰子各投一次,记事件A为“三个点数都不相同”,B为“至少出现一个6点,则概率P(A/B)P(A/B)=P(AB)/P(B)P(AB)=60/216,P(B)=1- P(B逆)=1- 5*5*5/(6*6*6)=1- 125/216= 91/216故:P(A/B)=(60/216)/(91/216)=60/91P(AB)=60/216?这](/uploads/image/z/1783443-3-3.jpg?t=%E5%B0%86%E4%B8%89%E9%A2%97%E9%AA%B0%E5%AD%90%E5%90%84%E6%8A%95%E4%B8%80%E6%AC%A1%2C%E8%AE%B0%E4%BA%8B%E4%BB%B6A%E4%B8%BA%E2%80%9C%E4%B8%89%E4%B8%AA%E7%82%B9%E6%95%B0%E9%83%BD%E4%B8%8D%E7%9B%B8%E5%90%8C%E2%80%9D%2CB%E4%B8%BA%E2%80%9C%E8%87%B3%E5%B0%91%E5%87%BA%E7%8E%B0%E4%B8%80%E4%B8%AA6%E7%82%B9%2C%E5%88%99%E6%A6%82%E7%8E%87P%28A%2FB%29P%28A%2FB%29%3DP%28AB%29%2FP%28B%29P%28AB%29%3D60%2F216%2CP%28B%29%3D1-+P%28B%E9%80%86%29%3D1-+5%2A5%2A5%2F%286%2A6%2A6%29%3D1-+125%2F216%3D+91%2F216%E6%95%85%3AP%28A%2FB%29%3D%2860%2F216%29%2F%2891%2F216%29%3D60%2F91P%28AB%29%3D60%2F216%3F%E8%BF%99)
将三颗骰子各投一次,记事件A为“三个点数都不相同”,B为“至少出现一个6点,则概率P(A/B)P(A/B)=P(AB)/P(B)P(AB)=60/216,P(B)=1- P(B逆)=1- 5*5*5/(6*6*6)=1- 125/216= 91/216故:P(A/B)=(60/216)/(91/216)=60/91P(AB)=60/216?这
将三颗骰子各投一次,记事件A为“三个点数都不相同”,B为“至少出现一个6点,则概率P(A/B)
P(A/B)=P(AB)/P(B)
P(AB)=60/216,P(B)=1- P(B逆)=1- 5*5*5/(6*6*6)=1- 125/216= 91/216
故:P(A/B)=(60/216)/(91/216)=60/91
P(AB)=60/216?这步看不懂、能说下么?
将三颗骰子各投一次,记事件A为“三个点数都不相同”,B为“至少出现一个6点,则概率P(A/B)P(A/B)=P(AB)/P(B)P(AB)=60/216,P(B)=1- P(B逆)=1- 5*5*5/(6*6*6)=1- 125/216= 91/216故:P(A/B)=(60/216)/(91/216)=60/91P(AB)=60/216?这
P(AB)表示同时满足A和B的概率
同时满足A、B的情况的排列个数(分步法):
1,首先,三颗骰子中选一颗,使其点数为6,有三种情况.
2,第二颗骰子点数为1~5,有五种情况.
3,第三颗骰子点数为1~5且与第二颗骰子点数不同,有四种情况.
∴排列总数 = 3*5*4 = 60(种)
而全排列 = 6!=216
∴根据概率的公式有
P(AB) = AB的可能情况排列总数 / 全排列
= 60 / 216
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