已知实数x、y满足x+2y=6,当1≤x≤3时,(y-1)/(x-2)的取值范围是
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![已知实数x、y满足x+2y=6,当1≤x≤3时,(y-1)/(x-2)的取值范围是](/uploads/image/z/1802654-62-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0x%E3%80%81y%E6%BB%A1%E8%B6%B3x%2B2y%3D6%2C%E5%BD%931%E2%89%A4x%E2%89%A43%E6%97%B6%2C%28y-1%29%2F%28x-2%29%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF)
已知实数x、y满足x+2y=6,当1≤x≤3时,(y-1)/(x-2)的取值范围是
已知实数x、y满足x+2y=6,当1≤x≤3时,(y-1)/(x-2)的取值范围是
已知实数x、y满足x+2y=6,当1≤x≤3时,(y-1)/(x-2)的取值范围是
先用x表示y,求出y的取植范围
y=x/2-3 代入x得-5/2≤y≤-3/2
(y-1)/(x-2)最小时 y-1最小 y-1=-7/2 x-2最大 x-2=1
(y-1)/(x-2)=-7/2
(y-1)/(x-2)最大时 x-2<0 且 x-2=-1/∞(无穷接近零)
(y-1)/(x-2)=∞
所以(y-1)/(x-2)∈(-7/2,∞)
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