1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.)1X2+2X3+3X4+...+nX(n+1)= ? 1X2+2X3+3X4+...+10X11= ?(写过程,如1/3 乘.)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/02 17:04:18
1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.)1X2+2X3+3X4+...+nX(n+1)= ?       1X2+2X3+3X4+...+10X11= ?(写过程,如1/3 乘.)

1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.)1X2+2X3+3X4+...+nX(n+1)= ? 1X2+2X3+3X4+...+10X11= ?(写过程,如1/3 乘.)
1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.)
1X2+2X3+3X4+...+nX(n+1)= ? 1X2+2X3+3X4+...+10X11= ?(写过程,如1/3 乘.)

1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.)1X2+2X3+3X4+...+nX(n+1)= ? 1X2+2X3+3X4+...+10X11= ?(写过程,如1/3 乘.)
原式 = \sum_{i=1}^{n}(i^2 + i)
= \sum_{i=1}^{n}{i^2} + \sum_{i=1}^{n}{i}
= n(n+1)(2n+1)/6 + n(n+1)/2