(6>5>4)+(FLOAT)(3/2)为什么等于1.0

(6>5>4)+(FLOAT)(3/2)为什么等于1.0 4╱5*(float)3＋（float）3*4/5=? 求x^3-15x^2+16x-80一个实根,下面程序怎么算不出来#include#includefloat f(float x){return ((x-5)*x-16)*x-80;}float xpoint(float x1,float x2){return (x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));}float root(float x1,float x2){float x,y,y1;y1=f(x1);do{ 求大虾们改错,此程序是求1-1/2+1/3-1/4+1/5-1/6+...1/n的和,但是有错误,输入大于等于2的数无效#includestdio.h#includemath.hfloat mymood(float n){float sum,a=1,b;sum=0;for(b=1;b 请斧正c中的错误-1#includefloat search(float (*p)[4],float n);main(){float score[3][4]={{11,22,33,44},{22,22,33,44},{33,44,55,66}};search(score,2);getch();}float search(float (*p)[4],float n){int i;printf(the input num:%d,n);for(i=0;i c语言的问题,求x^3-5x^2+16x-80的根,我用的弦截法,但是出错#include#includefloat f(float x){float y;y=x*(x*x-5*x+16)-80;return y;}float xpoint(float x1,float x2){float root;root=(f(x2)*x1-x2*f(x1))/(f(x2)-f(x1));return root;}void main() A)static int a[ ][ ]={{0,1,5},{2,4,7},{1,6,8}}; B)static float a[3][ ]={{0A)static int a[ ][ ]={{0,1,5},{2,4,7},{1,6,8}}; B)static float a[3][ ]={{0,1,5},{2,4,7},{1,6,8}}; C) static int a[ ][3]={0,1,5,2,4,7,1,6}; D)static float a[3][3]={(0,1,5),(2,4, float[] X = new float[] { 1,3,8 }; float[] Y = new float[] { 4,6,16 }; int i = 0; float ki;do{ki = (Y[i + 1] - Y[i]) / (X[i + 1] - X[i]);Console.WriteLine(ki={0},ki);i++;}while (i 用弦切法求f(x) =x^3 - 5x^2 + 16x - 80 的根,求证一下那里出问题了,输入-1 和8,结果是6.75.#include #include float t(float x){return (x*x*x - 5.0*x*x + 16*x - 80); }float t(float x1,float x2);{return ((x1 * f(x2) - x2 * f(x1)) / (f( C语言float a[5][3],*p[3];p[0]＝a[0];p[2]＝a[4]是什么意思?float a[5][3],*p[3];p[0]＝a[0];p[2]＝a[4]是什么意思? 以下程序的功能是用二分法求方程2X³-4X²+3X-6=0 的根,要求绝对误差不超过0.0001. 求填空.#include stdio.hfloat f(float){ return(2*x*x*x-4*x*x-3*x-6);}main(){float m=-100,n=90,r; r=(m+n)/2;while(_____________*f(n)! C语言指针问题 *score 与score 有什么区别#includemain(){void average(float *p,int n);void search(float (*p)[4],int n);float score[3][4]={{65,67,70,60},{80,87,90,81},{90,99,100,98}};average(* score,12);search(score,2);}void average(float * p float 用C语言求方程的根,用3个函数分别求当大于0、等于0和小于0时的根并输出结果.从主函数中输入abc的值.#include #include float zero(float a,float b){float x1,x2;x1=(-b)/(2*a);x2=(-b)/(2*a);}float one(float a,float b,flo 编写由三角形三边求面积的函数.#includefloat kig(float x, float y,float z);main(){ float s,a,b,c; scanf(%f%f%f,&a,&b,&c); s=kig(a,b,c); printf(s=%f ,kig(a,b,c));}float kig(float x,float y,float z){ float p; p=1/4*(2*x*z+y*y-x*x-z*z); C牛顿迭代法求根//牛顿迭代法求2*x*x*x-4.5*x*x+3*x-6=0 在（-10,10）之间的根.写出程序.Xn+1=Xn-f(Xn)/f'(Xn),#include #include float f(float x){return(2*x*x*x-4.5*x*x+3*x-6);}float f1(float x){return(6*x*x-9*x-3);}void main(){float fun(float x) { float y; y=3*x-4; return y; }以上函数值的类型为什么是int?怎么不是float呢? 设a=2,b=3,x=3.5,y=2.5,表达式(float)(a+b)/2+(int)x%2/4 的值为____2.5__