化简并计算1/√X(X+1)+1/(√X+1)(√X+2)乘以1/(√X+2)(√X+3)+……+ 1/(√X+19)(√X+20)=____结果中分母不含根式
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/25 20:18:27
![化简并计算1/√X(X+1)+1/(√X+1)(√X+2)乘以1/(√X+2)(√X+3)+……+ 1/(√X+19)(√X+20)=____结果中分母不含根式](/uploads/image/z/2832165-45-5.jpg?t=%E5%8C%96%E7%AE%80%E5%B9%B6%E8%AE%A1%E7%AE%971%2F%E2%88%9AX%28X%2B1%29%2B1%2F%EF%BC%88%E2%88%9AX%2B1%EF%BC%89%EF%BC%88%E2%88%9AX%2B2%EF%BC%89%E4%B9%98%E4%BB%A51%2F%EF%BC%88%E2%88%9AX%2B2%EF%BC%89%EF%BC%88%E2%88%9AX%2B3%EF%BC%89%2B%E2%80%A6%E2%80%A6%2B+1%2F%EF%BC%88%E2%88%9AX%2B19%EF%BC%89%EF%BC%88%E2%88%9AX%2B20%EF%BC%89%3D____%E7%BB%93%E6%9E%9C%E4%B8%AD%E5%88%86%E6%AF%8D%E4%B8%8D%E5%90%AB%E6%A0%B9%E5%BC%8F)
化简并计算1/√X(X+1)+1/(√X+1)(√X+2)乘以1/(√X+2)(√X+3)+……+ 1/(√X+19)(√X+20)=____结果中分母不含根式
化简并计算1/√X(X+1)+1/(√X+1)(√X+2)乘以1/(√X+2)(√X+3)+……+ 1/(√X+19)(√X+20)=____
结果中分母不含根式
化简并计算1/√X(X+1)+1/(√X+1)(√X+2)乘以1/(√X+2)(√X+3)+……+ 1/(√X+19)(√X+20)=____结果中分母不含根式
=1/√x-1/(√x+1)+1/(√x+1)-1/(√x+2)+1/(√x+2)-……-1/(√x+19)+1/(√x+19)-1/(√x+20)
=1/√x-1/(√x+20)
=√x/x-(√x-20)/x-400
=(x√x-400√x-x√x+20x)/x(x-400)
=(20x-400√x)/x(x-400)
=(20x-400√x)/x(x-400)
计算并化简√x-2/x
计算并化简f(x+△x)-f(x)/△xf(x)=c 常数 f(x)=x^2 f(x)=1/x f(x)=根号x
数学化简计算(x+1)(x-1)(x^2-x+1)(x^2+x+1)
计算(x^2+2x+1/x+2)/(x^2-1/x^2+2x)*(x-1/x),并求当x=-3/2时的值
化简并计算1/√X(X+1)+1/(√X+1)(√X+2)乘以1/(√X+2)(√X+3)+……+ 1/(√X+19)(√X+20)=____结果中分母不含根式
计算√x-1+√1-x+x²-2x+3,计算√x-1+√1-x+x²-2x+3急!对了加十分
求y=lg(x-1)+sinx/(√x+1)定义域,并计算x=2时的函数值
计算:x(x^2+x-1)-(x^2-x+1)
计算(X²-2X分之X+2-X-2分之X-1)÷X分之X+3,并求当X=3时原式的值
微积分问题.计算无穷积分,并判断敛散性∫(1/√x) dx微积分问题.计算无穷积分,并判断敛散性∫ (1/√x) dx
计算【x-1】【x²+x+1】
计算:x/(1-x)-1/(x-3)
计算:|3-x|+|x-1|(x>5)
求教这三道题怎么求导并化简1.f(x)= x^2 / √(x^2+1)2.g(x)= (x+1)^8 * e^2x3.f(x)= e^√x / (x-3)
求教这三道题怎么求导并化简(要过程)1.f(x)= x^2 / √(x^2+1)2.g(x)= (x+1)^8 * e^2x3.f(x)= e^√x / (x-3)
已知f(x)=(1+x)/(1-x),求f(1/x)并化简.
【计算啊 - -】(1/2)x√4x+6x√x/9 - 2x^2√1/x
计算:2x√x-x²√(1/x³)+6x√(x/4)(要过程)