cosπ/8和sinπ/8怎么算啊额 不好意思了都...
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cosπ/8和sinπ/8怎么算啊额 不好意思了都...
cosπ/8和sinπ/8怎么算啊
额 不好意思了都...
cosπ/8和sinπ/8怎么算啊额 不好意思了都...
(cosπ/8)^2=(1+cosπ/4)/2=(2+根号2)/4
开方即得cosπ/8
同理(sinπ/8)^2=(1-cosπ/4)/2=(2-根号2)/4
开方即得sinπ/8
cosπ/8和sinπ/8怎么算啊额 不好意思了都...
2sinπ/8cosπ/8怎么得到sinπ/4?
2sin的平方xsin^2(π/8)-cos^2(π/8) 我知道是2sin^2-1 但是不知道怎么计算啊..
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
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sinπ/8×cosπ/8
sinπ/8×cosπ/8
sinπ/8*cosπ/8
sinπ/8cosπ/8=( )
已知向量m=(Cosθ,Sinθ)和n(根号2 -Sinθ,Cosθ),且Im+nl= 求Cos(θ/2+π/8)
不求值,分别比较下列各组中两个三角函数值的大小(1)sin(-π/7)和sin(-π/5)(2)cos(4/7)π与cos(5/8)π
(cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8)
(cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8).
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cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
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sin kπ/4(k从1到n)的和为什么等于{cos[π/8]-cos[(n+1/2)π/4]}/2sin(π/8)?