sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)我晕,正的还是负的
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/23 14:19:36
![sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)我晕,正的还是负的](/uploads/image/z/364936-40-6.jpg?t=sin%28%CE%B8-5%CF%80%29cos%5B%28-%CF%80%2F2%29-%CE%B8%5Dcos%288%CF%80-%CE%B8%29%7D%2Fsin%5B%CE%B8-%283%CF%80%2F2%29%5Dsin%28-%CE%B8-4%CF%80%29%E6%88%91%E6%99%95%EF%BC%8C%E6%AD%A3%E7%9A%84%E8%BF%98%E6%98%AF%E8%B4%9F%E7%9A%84)
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)我晕,正的还是负的
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)
我晕,正的还是负的
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)我晕,正的还是负的
{ sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)
=(-sinθ) ( -sinθ ) cosθ) /cosθ] (-sinθ)
=-sinθ
=sinθsinθcosθ/cosθsinθ=sinθ
应该没什么问题。 你看不出来么?当然是负的了。把书上的诱导公式看看对照一下。 不要只追求一个答案。
=(-sinθ) ( -sinθ ) cosθ) /cosθ] (-sinθ) =-sinθ
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sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)我晕,正的还是负的
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