整式的加减 (15 18:21:9)已知Y=AX的5次方+BX的3次方+CX-5,当X=-3时,Y=7,那么X=3时,求Y的值
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![整式的加减 (15 18:21:9)已知Y=AX的5次方+BX的3次方+CX-5,当X=-3时,Y=7,那么X=3时,求Y的值](/uploads/image/z/3780245-29-5.jpg?t=%E6%95%B4%E5%BC%8F%E7%9A%84%E5%8A%A0%E5%87%8F+%2815+18%3A21%3A9%29%E5%B7%B2%E7%9F%A5Y%3DAX%E7%9A%845%E6%AC%A1%E6%96%B9%2BBX%E7%9A%843%E6%AC%A1%E6%96%B9%2BCX-5%2C%E5%BD%93X%3D-3%E6%97%B6%2CY%3D7%2C%E9%82%A3%E4%B9%88X%3D3%E6%97%B6%2C%E6%B1%82Y%E7%9A%84%E5%80%BC)
整式的加减 (15 18:21:9)已知Y=AX的5次方+BX的3次方+CX-5,当X=-3时,Y=7,那么X=3时,求Y的值
整式的加减 (15 18:21:9)
已知Y=AX的5次方+BX的3次方+CX-5,当X=-3时,Y=7,那么X=3时,求Y的值
整式的加减 (15 18:21:9)已知Y=AX的5次方+BX的3次方+CX-5,当X=-3时,Y=7,那么X=3时,求Y的值
x=-3,y=-3^5a-3^3b-3c-5=7
3^5a+3^3b+c=-12
x=3,y=3^5a+3^3b+c-5=-12-5=-17
=-3,y=-3^5a-3^3b-3c-5=7
3^5a+3^3b+c=-12
x=3,y=3^5a+3^3b+c-5=-12-5=-17
解题过程如下:
Y=AX^5+BX^3+CX-5当X=-3时,则
Y=-A3^5-B3^3-3C-5=-(A3^5+B3^3+3C)-5=7
解得:A3^5+B3^3+3C=-12
而当X=3时
Y=A3^5+B3^3+3C-5=-12-5=-17
当x=-3时 7=-3³×3²a-3³b-3c-5
=-(3³×3²a+3³b+3c)-5
3³×3²a+3³b+3c=-(7+5)
=-12
当x=3时 y=3&su...
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当x=-3时 7=-3³×3²a-3³b-3c-5
=-(3³×3²a+3³b+3c)-5
3³×3²a+3³b+3c=-(7+5)
=-12
当x=3时 y=3³×3²a+3³b+3c-5
=-12-5
=-17
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