若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,...若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,则a=__________=
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![若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,...若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,则a=__________=](/uploads/image/z/5264284-4-4.jpg?t=%E8%8B%A5%E5%8F%98%E9%87%8Fx%E3%80%81y%E6%BB%A1%E8%B6%B3%E3%80%90x%EF%BC%8By%EF%BC%8B2%E2%89%A60%EF%BC%9Bx%EF%BC%8Dy%EF%BC%8B4%E2%89%A70%EF%BC%9By%E2%89%A7a%E3%80%91%2C%E8%8B%A52x%EF%BC%8Dy%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA-1%2C...%E8%8B%A5%E5%8F%98%E9%87%8Fx%E3%80%81y%E6%BB%A1%E8%B6%B3%E3%80%90x%EF%BC%8By%EF%BC%8B2%E2%89%A60%EF%BC%9Bx%EF%BC%8Dy%EF%BC%8B4%E2%89%A70%EF%BC%9By%E2%89%A7a%E3%80%91%2C%E8%8B%A52x%EF%BC%8Dy%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA-1%2C%E5%88%99a%3D__________%3D)
若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,...若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,则a=__________=
若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,...
若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,则a=__________
=
若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,...若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,则a=__________=
首先画出4个关系式的坐标图,知道x+y+2=0斜率为1,而设2x-y=z,也就是y=2x-z斜率为2,大于1,所以当y取最小时(y=a),z为最大值-1,交点为直线y=a与x+y+2
-1
先画图,根据方程组x+y+2≤0, x-y+4≥0, y≥a再用线线规划设Z=2x-y即Y=2X-Z平行移动,就可以看出X+Y+2=0与Y=a的交点是使Z=2x-y取到最小值的地方,此时Y=a,X=-a-2,Z=-1。所以-1=-2a-2+a得到a=-1
变量x,y满足x-2y=0,x
若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,...若变量x、y满足【x+y+2≦0;x-y+4≧0;y≧a】,若2x-y的最大值为-1,则a=__________=
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