LINGO 帮我改改,我想要输出的结果是s(1)=1,s(2)=4,s(3)=2,s(4)=3,model:sets:a/1,2,3,4/;b/1,2,3,4/;c(a,b):x;sx/1,2,3,4/:s;endsetsdata:x= 0 0 0 10 0 1 00 0 0 00 1 0 0;enddatacalc:s(1)=1;@for(sx(k)|k#ge#1 #and# k#le#3:@for(c(i,j)|j#ge#2 #and# j
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![LINGO 帮我改改,我想要输出的结果是s(1)=1,s(2)=4,s(3)=2,s(4)=3,model:sets:a/1,2,3,4/;b/1,2,3,4/;c(a,b):x;sx/1,2,3,4/:s;endsetsdata:x= 0 0 0 10 0 1 00 0 0 00 1 0 0;enddatacalc:s(1)=1;@for(sx(k)|k#ge#1 #and# k#le#3:@for(c(i,j)|j#ge#2 #and# j](/uploads/image/z/7202587-67-7.jpg?t=LINGO+%E5%B8%AE%E6%88%91%E6%94%B9%E6%94%B9%2C%E6%88%91%E6%83%B3%E8%A6%81%E8%BE%93%E5%87%BA%E7%9A%84%E7%BB%93%E6%9E%9C%E6%98%AFs%281%29%3D1%2Cs%282%29%3D4%2Cs%283%29%3D2%2Cs%284%29%3D3%2Cmodel%3Asets%3Aa%2F1%2C2%2C3%2C4%2F%3Bb%2F1%2C2%2C3%2C4%2F%3Bc%28a%2Cb%29%3Ax%3Bsx%2F1%2C2%2C3%2C4%2F%3As%3Bendsetsdata%3Ax%3D+0+0+0+10+0+1+00+0+0+00+1+0+0%3Benddatacalc%3As%281%29%3D1%3B%40for%28sx%28k%29%7Ck%23ge%231+%23and%23+k%23le%233%3A%40for%28c%28i%2Cj%29%7Cj%23ge%232+%23and%23+j)
LINGO 帮我改改,我想要输出的结果是s(1)=1,s(2)=4,s(3)=2,s(4)=3,model:sets:a/1,2,3,4/;b/1,2,3,4/;c(a,b):x;sx/1,2,3,4/:s;endsetsdata:x= 0 0 0 10 0 1 00 0 0 00 1 0 0;enddatacalc:s(1)=1;@for(sx(k)|k#ge#1 #and# k#le#3:@for(c(i,j)|j#ge#2 #and# j
LINGO 帮我改改,我想要输出的结果是s(1)=1,s(2)=4,s(3)=2,s(4)=3,
model:
sets:
a/1,2,3,4/;
b/1,2,3,4/;
c(a,b):x;
sx/1,2,3,4/:s;
endsets
data:
x= 0 0 0 1
0 0 1 0
0 0 0 0
0 1 0 0;
enddata
calc:
s(1)=1;
@for(sx(k)|k#ge#1 #and# k#le#3:
@for(c(i,j)|j#ge#2 #and# j#le#4:
s(k+1)=@if(x(s(k),j)#eq#1,j,null)
);
);
endcalc
end
LINGO 帮我改改,我想要输出的结果是s(1)=1,s(2)=4,s(3)=2,s(4)=3,model:sets:a/1,2,3,4/;b/1,2,3,4/;c(a,b):x;sx/1,2,3,4/:s;endsetsdata:x= 0 0 0 10 0 1 00 0 0 00 1 0 0;enddatacalc:s(1)=1;@for(sx(k)|k#ge#1 #and# k#le#3:@for(c(i,j)|j#ge#2 #and# j
你的是这个逻辑?
! s(1) = 1;! k = 1, s(1) = 1, 第 1 行 第 4 个为 1, 所以 s(2) = 4 ;
! k = 2, s(2) = 4, 第 4 行 第 2 个为 1, 所以 s(3) = 2;
! k = 3, s(3) = 3, 第 2 行 第 3 个为 1, 所以 s(4) = 3;