lingo 拿不出正确的解MIN=500*(t1+16)*z+50*(t2+16)*j;(500*t1*z+35*t2*j)*(1+(a+20*100)*b+((a+20*100)^2)*(b^3)+((a+20*100)^3)*(b^6)+((a+20*100)^4)*(b^10))>=80000000;t1=1;z>=1;j>=1;end出来的答案是t1,t2,z,j都取1的时候,这样不合理啊
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/24 11:42:12
![lingo 拿不出正确的解MIN=500*(t1+16)*z+50*(t2+16)*j;(500*t1*z+35*t2*j)*(1+(a+20*100)*b+((a+20*100)^2)*(b^3)+((a+20*100)^3)*(b^6)+((a+20*100)^4)*(b^10))>=80000000;t1=1;z>=1;j>=1;end出来的答案是t1,t2,z,j都取1的时候,这样不合理啊](/uploads/image/z/8881512-24-2.jpg?t=lingo+%E6%8B%BF%E4%B8%8D%E5%87%BA%E6%AD%A3%E7%A1%AE%E7%9A%84%E8%A7%A3MIN%3D500%2A%28t1%2B16%29%2Az%2B50%2A%28t2%2B16%29%2Aj%3B%28500%2At1%2Az%2B35%2At2%2Aj%29%2A%281%2B%28a%2B20%2A100%29%2Ab%2B%28%28a%2B20%2A100%29%5E2%29%2A%28b%5E3%29%2B%28%28a%2B20%2A100%29%5E3%29%2A%28b%5E6%29%2B%28%28a%2B20%2A100%29%5E4%29%2A%28b%5E10%29%29%3E%3D80000000%3Bt1%3D1%3Bz%3E%3D1%3Bj%3E%3D1%3Bend%E5%87%BA%E6%9D%A5%E7%9A%84%E7%AD%94%E6%A1%88%E6%98%AFt1%2Ct2%2Cz%2Cj%E9%83%BD%E5%8F%961%E7%9A%84%E6%97%B6%E5%80%99%2C%E8%BF%99%E6%A0%B7%E4%B8%8D%E5%90%88%E7%90%86%E5%95%8A)
lingo 拿不出正确的解MIN=500*(t1+16)*z+50*(t2+16)*j;(500*t1*z+35*t2*j)*(1+(a+20*100)*b+((a+20*100)^2)*(b^3)+((a+20*100)^3)*(b^6)+((a+20*100)^4)*(b^10))>=80000000;t1=1;z>=1;j>=1;end出来的答案是t1,t2,z,j都取1的时候,这样不合理啊
lingo 拿不出正确的解
MIN=500*(t1+16)*z+50*(t2+16)*j;
(500*t1*z+35*t2*j)*(1+(a+20*100)*b+((a+20*100)^2)*(b^3)+((a+20*100)^3)*(b^6)+((a+20*100)^4)*(b^10))>=80000000;
t1=1;
z>=1;
j>=1;
end
出来的答案是t1,t2,z,j都取1的时候,这样不合理啊
lingo 拿不出正确的解MIN=500*(t1+16)*z+50*(t2+16)*j;(500*t1*z+35*t2*j)*(1+(a+20*100)*b+((a+20*100)^2)*(b^3)+((a+20*100)^3)*(b^6)+((a+20*100)^4)*(b^10))>=80000000;t1=1;z>=1;j>=1;end出来的答案是t1,t2,z,j都取1的时候,这样不合理啊
其实结果还是很合理的啊,主要原因是目标函数中不含a和b,而t1,t2,z,j都有下界1,势必如果取前述各值为下界,而且它们同时满足了第一个约束条件的话,就可以取得最小化结果.
以上个人愚见,希望有益于你认识这个问题,祝好运!
怎么不合理了 明显这时候应该是最小的 相当合理了