C语言简单计算器,支持加减乘除乘方运算,每步要有注释,求助C语言高手解决,谢谢!#include double add(double a,double b){ double s; s=a+b; return s;}double sub(double a,double b){ double s; s=a-b; return s;}double multi(
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![C语言简单计算器,支持加减乘除乘方运算,每步要有注释,求助C语言高手解决,谢谢!#include double add(double a,double b){ double s; s=a+b; return s;}double sub(double a,double b){ double s; s=a-b; return s;}double multi(](/uploads/image/z/955471-31-1.jpg?t=C%E8%AF%AD%E8%A8%80%E7%AE%80%E5%8D%95%E8%AE%A1%E7%AE%97%E5%99%A8%2C%E6%94%AF%E6%8C%81%E5%8A%A0%E5%87%8F%E4%B9%98%E9%99%A4%E4%B9%98%E6%96%B9%E8%BF%90%E7%AE%97%2C%E6%AF%8F%E6%AD%A5%E8%A6%81%E6%9C%89%E6%B3%A8%E9%87%8A%2C%E6%B1%82%E5%8A%A9C%E8%AF%AD%E8%A8%80%E9%AB%98%E6%89%8B%E8%A7%A3%E5%86%B3%2C%E8%B0%A2%E8%B0%A2%21%23include+double+add%28double+a%2Cdouble+b%29%7B++double+s%3B++s%3Da%2Bb%3B++return+s%3B%7Ddouble+sub%28double+a%2Cdouble+b%29%7B++double+s%3B++s%3Da-b%3B++return+s%3B%7Ddouble+multi%28)
C语言简单计算器,支持加减乘除乘方运算,每步要有注释,求助C语言高手解决,谢谢!#include double add(double a,double b){ double s; s=a+b; return s;}double sub(double a,double b){ double s; s=a-b; return s;}double multi(
C语言简单计算器,支持加减乘除乘方运算,每步要有注释,求助C语言高手解决,谢谢!
#include
double add(double a,double b)
{
double s;
s=a+b;
return s;
}
double sub(double a,double b)
{
double s;
s=a-b;
return s;
}
double multi(double a,double b)
{
double s;
s=a*b;
return s;
}
double div(double a,double b)
{
double s;
s=a/b;
return s;
}
double power(double a,double b)
{
int i=0;
double s=1.0;
if(b==0)
return s=1;
else
{
for (i=1;i
C语言简单计算器,支持加减乘除乘方运算,每步要有注释,求助C语言高手解决,谢谢!#include double add(double a,double b){ double s; s=a+b; return s;}double sub(double a,double b){ double s; s=a-b; return s;}double multi(
这个你都看不懂?看程序需要点耐心的
读函数,关键是掌握方法,哪怕是初学,先从main函数下手读,到它调用函数了,再看它调用的函数是干吗用的,上定义哪个函数的地方找;像这么简单的函数应该一看就能明白了;这个计算器的程序只能实现最简单的 两个数字的运算,除了累乘函数;如果有兴趣你不妨自己写下多个数字的运算,包括考虑优先级,再有实力的话 可以试一下有括号的情况
#include
/*加法函数*/
double add(double a,double b)
{
double s;
s=a+b;
return s;
}
/*减法函数*/
double sub(double a,double b)
{
double s;
s=a-b;
return s;
}
/*乘法函数*/
double multi(double a,double b)
{
double s;
s=a*b;
return s;
}
/*除法函数*/
double div(double a,double b)
{
double s;
s=a/b;
return s;
}
/*累乘函数*/
double power(double a,double b)
{
int i=0;
double s=1.0;
if(b==0) // 如果是0个数字相乘,返回答案 1
return s=1;
else //如果相乘数字大于1 对他们累乘
{
for (i=1;i