sin285°-cos105°=

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 11:43:23
sin285°-cos105°=

sin285°-cos105°=
sin285°-cos105°=

sin285°-cos105°=
sin285°-cos105°
=sin(270°+15°)-cos(90°+15°)
=-cos15°+sin15°
=√2(sin15°cos45°-cos15°sin45°)
=√2sin(15°-45°)
=√2sin(-30°)
=-√2/2

负二分之根号2
sin285-cos105=
--sin105--cos105=--根号2sin(105+45)=负二分之根号2

=sin285+sin15
=2sin150cos135
=cos135
=负二分之根号2

sin(180+105)-cos105
=sin105-cos105
=√2 sin(105+45)
=√2sin150
= -√2

sin285=sin(360-75)=sin75。cos105=cos(180-75)=-cos75。所以原题等于sin75+cos75,又sin75=sin(45+30)=√2/2×√3/2+√2/2×1/2=(√6+√2)/4。cos75=cos(45+30)=√2/2×√3/2-√2/2×1/2=(√6-√2)/4。所以原式=(√6+√2+√6-√2)/4=√6/2